Theory of Graviton Fields Essay -- Atomic Structures

The Source, Nature, and Generation of the Graviton Field Summary The paper examines the possibility that atomic structures exists as complete self sustaining entities in identical form throughout the Universe, without any form of external input. The paper examines the energy budget of an atomic structure and concludes that gravitational attraction forms an inherent function of the structure in the form of low level quanta ejected from the structure as the final spent particle. It is postulated that all so far identified sub atomic particles are sourced from a single particle, in the central, heavy core, giving up energy in a Bohr/quanta manner as they perform particular functions within the structure. These various energy demands are consistent with the often quoted atomic half life of 1032 years. A mechanism by which a self sustaining structure generates an attraction field is described, together with the mechanism by which multiple structures interact. The process relating to interaction within a single structure is also described. The paper examines the nature of the gravitational field. It follows from the prognosis that the atomic particles identified so far from accelerators, are formed by a quanta/energy degradation which takes place. The core exists as a single entity in an electron, this same particle forming an assembly in all the structures identified in the periodic table. Key Index Phrases The nature of the graviton field. Introduction In the theory now presented by the author, the long sought graviton particle is viewed as the 'Spent' or residual, low energy particle arising from the proton/neutron/electron exponential decay process. This decay represents the energy required to support th... ....dï  ¦,dï  ±,G.M] . dR Since d(E) = R.dF d (E) = ï  ²,. G.M. R2 dï  ¦,.dï  ±, Over the whole surface ïÆ' ¥,E = 2ï  ², ï  ¦,ï  ±,G.M.R2 Substituting figures, E = 56.7x1024 kJ A.2.6 Energy requirement per atom dE = 56.7x1024 kJ 0.71x1050 = 7.98x10-23 kJ Converting to eV d (eV) = 0.0253 eV for Vanadium.